441f^2-1=0

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Solution for 441f^2-1=0 equation:



441f^2-1=0
a = 441; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·441·(-1)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*441}=\frac{-42}{882} =-1/21 $
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*441}=\frac{42}{882} =1/21 $

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